Question

In case of free fall velocity on reaching the ground is v at halftime the maximum height velocity is (m/s)

Answer 1

Solution :-

Provided :-

• Velocity at reaching ground = v

• It is a freefall

Now it ask height at t = t/2

We have

- h = u(t) - 1/2 gt²

Here it is a freefall = u = 0

→ -h = -1/2 gt²

→ h = 1/2 gt²

Now H travelled when t = t/2

→ H = 1/2 g(t/2)²

→ H = 1/8 gt²

or H = 1/4 h from Top

→ H = h - h/4

→ H = 3h/4 from ground