Question

In case of oxygen, Mn shows the highest oxidation state of +7. This is because Mn forms pπ–dπ multiple bonds using 2p orbitals of oxygen and 3d orbitals of Mn. With F, Mn displays an oxidation state of +4 because of the single bond formation caused by the unavailability of 2p orbitals in F for multiple bonding.

Answer 1

because oxygen very heavy electric negative charge