Question

in ccp type structure if half of the fcc atoms are removed then %age void in unit cell is spproximately​

Answer 1

Answer:

77%

Explanation:

In CCP there are 4 atoms.( 1 corner and 3 face centered atoms.)

If half of the face centered atoms are removed then,

No. of face centred atoms= (1/2 )* (6/2)= 3/2.

Therefore total no. of atoms = 1( corner) + 3/2= 5/2.

Packing efficiency =(( 4/3 * pi * r^3 * 5/2) / a^3) * 100

In CCP a = 2√2r

Hence packing efficiency = 23%

Therefore % void = 100-23 = 77%.