Question

In ΔCDE, the measure of ∠E=90°, ED = 63, DC = 65, and CE = 16. What is the value of the sine of ∠D to the nearest hundredth?

Answer 1

Answer:

SinD=(CE)//(CD)

SIND=16/65=0.246

Answer 2

Answer:

The value of sine of ∠$D$ is $0.246$.

Step-by-step explanation:

Sine value : In a right-angled triangle, the sine of an angle is the ratio of the length of the perpendicular to the length of the hypotenuse.

It gives the value of the sine function of the right triangle's angle between the base and hypotenuse.

In the triangle Δ$ABC$,

The hypotenuse is $DC=65$ (side opposite to the right-angle)

$Sin(D)=\frac{opposite}{hypotenuse}$

The side opposite to ∠$D$ is $CE$

$Sin(D)=\frac{CE}{DC}$

$Sin(D)=\frac{16}{65}$

$Sin(D)= 0.246$

Hence the value of sine of ∠$D$ is $0.246$.