Question

in chromium atom, in ground state , find the number of occupied orbitals.

Answer 1

Answer:

The configuration of  

24Cr is 1s2 ,2s 2 ,2p 6 ,3s 2 ,3p 6 ,3d 5 ,4s 1

Therefore,  total s-orbitals=4

total p-orbitals=6

total d-orbitals=5 and thus

Thus, total orbitals =4+6+5=15.

Explanation:

Answer 2

In the chromium atom, in the ground state, the number of occupied orbitals is 15.

Ground state:

• A quantum mechanical system's ground state is its stationary, lowest energy state; this energy is often referred to as the system's zero-point energy.
• Any state that has more energy than the ground state is said to be excited.
• Consider an atom of carbon with the following electron arrangement. By moving one or more electrons to different orbitals, the energy of the electrons in this carbon atom cannot be reduced. This carbon atom is a ground-state atom as a result.

Calculation of orbitals:

• The configuration of  $^{24} Cr$ is $1s^{2}, 2s^{2}, 2p^{6} , 3s^{2} , 3p^{6} , 3d^{5} ,4s^{1}$.
• Total s-orbitals = 4
• total p-orbitals=6
• total d-orbitals=5 and thus
• Thus, total orbitals = 4+6+5 = 15.

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