In class 10 A, there are 20 boys and 20 girls. In 10 B, there are 15 boys and 25 girls. One student is to be selected from each class. [3] (i) What is the probability of both being girls? (ii) What is the probability of both being boys? (iii) What is the probability of one boy and one girl?
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Answer:
1) P{2 girls}=(5/16)
2)P{2boys}=(3/16)
3)P{1 girl,1boy}=(8/16)=(1/2)
Explanation:
CLASS 10A: 20boys,20girls
CLASS 10B: 15boys,25girls
In class 10A
P{Boys}=20/40=1/2
P{Girls}=20/40=1/2
In class 10B
P{Boys}=15/40=3/8
P{Girls}=25/40=5/8
1)P{2 girls}=Probability of girls in 10A ×Probability of girls in 10B
1/2 × 5/8 = 5/16......P1
2)P{2 boys}=Probability of boys in 10A × Probability of boys in 10B
1/2 × 3/8 = 3/16 ......P2
3)P{1 boy, 1girl}= No:of events - (P1+P2) . That is: P{no 2 boys or 2 girls)
=(16/16) - (5/16 + 3/16)
=(16/16) - (8/16)
=(8/16)
= 1/2
HOPE IT HELPS!
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