CBSE BOARD X, asked by harshinikirubanand, 11 months ago

In class 10 A, there are 20 boys and 20 girls. In 10 B, there are 15 boys and 25 girls. One student is to be selected from each class. [3] (i) What is the probability of both being girls? (ii) What is the probability of both being boys? (iii) What is the probability of one boy and one girl?

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Answers

Answered by akshayroopan2004
2

Answer:

1) P{2 girls}=(5/16)

2)P{2boys}=(3/16)

3)P{1 girl,1boy}=(8/16)=(1/2)

Explanation:

CLASS 10A: 20boys,20girls

CLASS 10B: 15boys,25girls

In class 10A

P{Boys}=20/40=1/2

P{Girls}=20/40=1/2

In class 10B

P{Boys}=15/40=3/8

P{Girls}=25/40=5/8

1)P{2 girls}=Probability of girls in 10A ×Probability of girls in 10B

1/2 × 5/8 = 5/16......P1

2)P{2 boys}=Probability of boys in 10A × Probability of boys in 10B

1/2 × 3/8 = 3/16 ......P2

3)P{1 boy, 1girl}= No:of events - (P1+P2) . That is: P{no 2 boys or 2 girls)

=(16/16) - (5/16 + 3/16)

=(16/16) - (8/16)

=(8/16)

= 1/2

HOPE IT HELPS!

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