In cos A=2/5,find the value of 4+4tan'2A
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Hi ,
cos A = 2/5 ---( 1 )
value of 4 + 4tan² A
= 4 ( 1 + tan² A )
= 4 sec² A
[ since 1 + tan² A = sec² A ]
= 4 / cos² A
[ since secA = 1/cosA ]
= 4 / ( 2/5 )²
[ from ( 1 ) ]
= 4 × ( 25 / 4 )
= 25
I hope this helps you.
:)
cos A = 2/5 ---( 1 )
value of 4 + 4tan² A
= 4 ( 1 + tan² A )
= 4 sec² A
[ since 1 + tan² A = sec² A ]
= 4 / cos² A
[ since secA = 1/cosA ]
= 4 / ( 2/5 )²
[ from ( 1 ) ]
= 4 × ( 25 / 4 )
= 25
I hope this helps you.
:)
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