in cyclic quadrilateral ABCD angleCAB=45 and angle ABC=100 then angleADB=?
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Make a circle.
Draw a cyclic quadrilateral and name it ABCD. JOin AC and BD.
Next, in triangle ABC,
We have angle BAC=45, angle ABC=100 therefore by angle sum property, We get angle BCA=35.
Angle BCA= angle BDA, as the are angles subtended by the same chord on the same side of the chord.
So you get,
Angle BDA= 35.
Hope you find this helpful!
Draw a cyclic quadrilateral and name it ABCD. JOin AC and BD.
Next, in triangle ABC,
We have angle BAC=45, angle ABC=100 therefore by angle sum property, We get angle BCA=35.
Angle BCA= angle BDA, as the are angles subtended by the same chord on the same side of the chord.
So you get,
Angle BDA= 35.
Hope you find this helpful!
Answered by
0
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