Question

In ∆ DEF, ∠E = 90°, DF – DE = 2 cm, EF = 6 cm. Find cos D + sin D. ANYONE HELP ME FAST PLEASE.



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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

1.4

given,

• ∆ DEF, ∠E = 90°
• DF – DE = 2 cm
• EF = 6 cm

to find,

the value of cos D + sin

solution,

Let DF be X

Then, DE= X-2

According to Pythagoras theorem,

H²= P²+ B²

DF²= (DE-2)² + EF²

X²= (X-2)² + 6²

X² = X² + 4 - 4X + 36

0 = - 4X + 40

4X = 40

X = 10

So,

DF= 10 ; DE= 8 ; EF =6

now, we need to find the value of cos D + sin D

cos D= base/ hypotenuse

sin D = perpendicular / hypotenuse

cos D + sin D= base/ hypotenuse + (perpendicular / hypotenuse)

Y = 8/10 + 6/10

Y = 14/10

Y = 1.4

cos D + sin D= 1.4

therefore, 1.4 is the required response.

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