Question

in determination method 1/3x×y=10/3;2x+1/4y=11/4​
please help

Answer 1

Answer:

this is very confused ..

Answer 2

★᭄ꦿ᭄QUESTION★᭄ꦿ᭄

determination method;

1/3x×y=10/3;2x+1/4y=11/4

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✰✰ ANSWER ✰✰

$\frac{1}{3} x + y = \frac{10}{3} \: - - - - - - (1)$

$2x + \frac{1}{4} y = \frac{11}{4} - - - - - (2)$

multiply equation (1) by 3 and multiply equation (2) by 4.

$3 \times \frac{1}{3} x + 3 \times y = 3 \times \frac{10}{3}$

4×2x +4×1/4y=4×11/4

$x + 3y = 10 - - - - - (3)$

$8x + y = 11 - - - - - (4)$

multiply equation (3) by 1.and multiply equation (4) by 3.

$1 \times x + 1 \times 3y = 1 \times 10$

$3 \times 8x + 3 \times y = 3 \times 11$

$x + 3y = 10 - - - -( 5)$

$24x + 3y = 33 - - - - (6)$

subtracting equation (5) and (6)

$x + 3y = 10$

$24x + 3y = 33$

$- \: \: \: \: - \: \: \: \: \: \: -$

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$- 23x = - 23$

$x = \frac{ - 23}{ - 23}$

$x = 1$

put the value x=1in equation (4)

$8x + y = 11 - - - - (4)$

$8 \times 1 + y = 11$

$8 + y = 11$

$y = 11 - 8$

$y = 3$

•⊰❂⊱• The solution is x=1 and y=3

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