Question

In distributing a sum of money among a number of boys, a man finds that rupees 2 is left if each be given 48P, but 60 paise will be wanting if he pays 61P to each. Find the the number of boys. This is a really complex problem for me as i can't get hold of the logic behind the sum even though I can do tougher problems!! Pls help fast!!!

[For the problem see question 45]

Answer 1

Answer:

Step-by-step explanation:

Let the total sum be M

Let the number of boys beX

Then from the given conditions

We get two quadratic equations

M-48X=200

M-61X= -60

SOLVING BOTH

We get X=20

M=1160

So the total boys are20 and the total amount is 1160

Hope you understood

Answer 2

Answer:

Msrk me as brainliest

Step-by-step explanation:

Let the total sum be M

Let the number of boys beX

Then from the given conditions

We get two quadratic equations

M-48X=200

M-61X= -60

SOLVING BOTH

We get X=20

M=1160

So the total boys are20 and the total amount is 1160

Hope you understood