In dobereiner's triad containing Li,Na,K if atomic masses of lithium and potassium are 6.9 and 39.1,then what will be the atomic mass of sodium?
aditya9552:
Li+K=NA (6.9+39.1 )÷2=23
Answers
Answered by
67
Dobereiner' triad : " The atomic mass of the middle element of triad is the arithmetic mean of the atomic masses of the other two elements. "
In this Question, It is given that if atomic masses of lithium and potassium are 6.9 and 39.1
Here, Atomic mass of Lithium = 6.9
Atomic mass and Potassium = 39.1
Now, Using Dobereiner' triad ,
Arithmetic mean = 39.1 + 6.9 ÷ 2
Sodium= 46/2
Sodium = 23
This, Required Atomic mass of Sodium is 23.
Answered by
18
Solution:- In dobereiner's triad containing Li,Na,K if atomic masses of lithium and potassium are 6.9 and 39.1.
Theory used here:-
Dobereiner's law of triads states that, the atomic mass of the middle element of a triad is the arithmetic mean of the atomic masses of the other two elements.
According to dobereiner, average of atomic masses of 1st and 3rd atom.
Atomic mass of Li = 6.9
Atomic mass of K = 39.1
Atomic mass of Na
=6.9+39.1 /2
=46/2 = 23u
Therefore, the atomic mass of Sodium (Na) = 23 u
[Answer: 23 u]
Theory used here:-
Dobereiner's law of triads states that, the atomic mass of the middle element of a triad is the arithmetic mean of the atomic masses of the other two elements.
According to dobereiner, average of atomic masses of 1st and 3rd atom.
Atomic mass of Li = 6.9
Atomic mass of K = 39.1
Atomic mass of Na
=6.9+39.1 /2
=46/2 = 23u
Therefore, the atomic mass of Sodium (Na) = 23 u
[Answer: 23 u]
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