in duma's method for estimation of nitrogen 0.84gm of at stp the percentage of nitrogen in the compound is
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mass of organic compound --- 0.246 g
mass of CO2 formed ----- 0.198 g
percentage of Carbon = 12 x mass of CO2 formed x 100
44 mass of organic compound
percentage of carbon = 12 /44 x 0.198/0.246 x 100
percentage of carbon = 2.376/10.824 x 100
% carbon = 0.2195 x 100
%carbon = 21.95
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21.95% of carbon is present in the compound
Percentage of hydrogen =2/18× mass of H2O/mass of compound×100 = 2×0.1014×100/18×0.246 = 4.58
Hence,the composition of compounds are
CARBON : 21.95%
HYDROGEN : 4.58%.
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