Question

In Duman's method of estimation of nitrogen 0.35 g of an organic compound gave 55 mL of nitrogen collected at 300 K temperature and 715 mm pressure. The percentage composition of nitrogen in the compond would be :
(Aqueous tension at 300 K = 15 mm)

Answer 1

Given:

Total mass of organic compound=0.468g

Mass of barium sulphate formed=0.688g

Since, 1 mol of BaSO4=233g of BaSO4=32g of sulphur

{molecular wt. Of Ba=137g, S=32g, O=16g}

{So, Molecular wt. Of BaSO4 =137+32+4(16)=233g}

Thus, 0.688g of BaSO4 contains g of sulphur=0.0917g of sulphur.

Therefore, percentage of sulphur==19.59%

Hence, the percentage of sulphur in the given compound is 19.59%