Question

in each of the following determine whether the given numbers are solutions of the given equations are not​

Answer 1

ANSWER= X²–3√3X+6=0

1. X²–3√3X+6=0

L.H.S= (√3)²–3√3×√3+6

=3–9+6

=0........Yes this is the zero of the polynomial

2. X²–3√3X+6=0

L.H.S= (–2√3)²–3√3×–2√3+6

=12+18+6

=36....No this is not the zero of the polynomial