In each of the following, use remainder theorem to find the remainder when f(x) is divided by g (x).
i) f (x) = 2x⁴ - 6x³+ 2x² - x+2 ; g(x) = x+2
ii) f (x) = x³ - 6x²+2x - 4 ; g (x) = 1 - 3x
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Given : f(x) = 2x⁴ - 6x³ + 2x² - x + 2, g(x) = x + 2
By remainder theorem, when f(x) is divided by g(x) = x + 2 , the remainder is equal to f(- 2) :
Now, f(x) = 2x⁴ - 6x³ + 2x² - x + 2
f (-2) = 2 (-2)⁴ - 6 (-2)³ + 2 (-2)²- (-2) + 2
f (-2) = 2 × 16 - 6 (- 8) + 2 (4) - (-2) + 2
f (-2) = 2 × 16 + 48 + 8 + 2 + 2
f (-2) = 32 + 48 + 12
f (-2) = 92
Hence, the remainder when f(x) is divided by g(x) is 92.
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