in electrolysis of water why is the volume of gas collected over 1 electrode double that of gas collected Over The Other electrode
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As we know two Hydrogen atoms and one oxygen atom is present in a water molecule.
When electricity is passed through the water, a decomposition reaction takes place and water divides into hydrogen and oxygen atoms.
2H2O → 2H2 + O2
As you can see in the above reaction. When water molecule breaks two Hydrogen molecules and a oxygen molecule produced.
=2 × H2
=O2
You can see the number of hydrogen molecule is double than the number of oxygen molecule.
So, the gas produced at cathode is double than the gas produced at anode.
I hope this will help you.
When electricity is passed through the water, a decomposition reaction takes place and water divides into hydrogen and oxygen atoms.
2H2O → 2H2 + O2
As you can see in the above reaction. When water molecule breaks two Hydrogen molecules and a oxygen molecule produced.
=2 × H2
=O2
You can see the number of hydrogen molecule is double than the number of oxygen molecule.
So, the gas produced at cathode is double than the gas produced at anode.
I hope this will help you.
kavya34:
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Answered by
61
hope it will help you.....
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