In enthalpies of formation for c2h4(g) and h2o(i) at 25'c and 1 atm pressure are 52,_394 and _286 kj/mol respectively, then enthalpy of combustion of c2h4(g) will be
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the chemical reaction is
Explanation:C2H4+3O2 GIVES 2CO2+2H20
THEN THE ENTHALPY OF COMBUSTION IS ENTHALPY OF FORMATION OF PRODUCTS-REACTANTS =[(2x-394)+(2x-286)]-[(52+0)]=-[788-572]-52=-1412kj/mol
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