In equaliteral triangle, prove that three times the square of one side is equal to four times the square of one of its altitudes ?
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It is given that :-
TRIANGLE (PQR) in which PQ = QR = RP also PN is perpendicular to QR
Now,
To Prove
3PQ² = 4AN²
Proof :-
In Triangle PNQ also in triangle PNR
PQ = PR (Given)
∠Q = ∠R = 60°
Therefore,
∆PNQ is congruent to ∆PNR (By SAA rule)
Therefore,
QN = NR =½QR
Now,
From right ∆PNQ
PQ² = PN² + QN² (Pythagoras theorem)
⇒ PN² + (½QR)²
⇒ PN² + ¼QR²
⇒ 4PQ² = 4PN² + QR²
⇒ 3PQ² = 4PN² (QR = PQ)
Therefore we get ,
3PQ² = 4PN²
Anonymous:
Awesome
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