Question

In equation 7x^2 + kx -3 =0 find the value of k for which x=2/3 is a solution of the given equation

Answer 1

Answer:

K= -1/6

Step-by-step explanation:

Hope this will help you solve the problem

Answer 2

Given:

7x^2 + kx -3 =0

x=2/3

To Find:

the value of k

Solution:

Let us substitute x=2/3 in the equation 7x^2 + kx -3 = 0

$7( { \frac{2}{3}) }^{2} + \frac{2k}{3} - 3 = 0$

$7( \frac{4}{9}) + \frac{2k}{3} - 3 = 0$

$\frac{28}{9} + \frac{2k}{3} - 3 = 0$

Rearranging by keeping the unknown term k to one side,

$\frac{2k}{3} = 3 - \frac{28}{9}$

$\frac{2k}{3} = \frac{27- 28}{9}$

2k = -1/3

k = -1/6

The value of k is -1/6