Question

In fig .1 , AB is parallel to PO and BC is parallel to OQ . Then find the value of (x+y)??​

Answer 1

Answer:

x=60°, y=60° x+y=120°

Step-by-step explanation:

Let the point of intersection of OP and BC be D.

∠QOP = ∠CDO                 [Alternate interior Angles]

∠CDP + ∠CDO = 180°       [Linear Pair]

y + 120° = 180°

y = 60°

x = y                                  [Corresponding Angles]

x = 60°

Hence, x+y = 60° + 60° = 120°