Question

In Fig. 10.101, PQ and PR are two tangents to a circle with centre O. If ∠QPR = 46°, then ∠QOR equals
A. 67°
B. 134°
C. 44°
D. 46°

Answer 1

Answer:

∠QPR + ∠OQP + ∠ORP + ∠QOR = 360° [Angles in a quadrilateral]

=> ∠OQP = ∠ORP = 90° [Tangents are perpendicular to the circle]

=> ∠QOR = 360 - 90 - 90 - 46

=> ∠QOR = 134°

Answer:- (b) 134°

____________

Answer 2

Answer:

C. 134°

Step-by-step explanation:

Sum of interior angles of a quadrilateral is 360°

⇒∠QOR=360°-90°-90°-46°

⇒∠QOR=134°