In Fig. 10.102, QR is a common tangent to the given circles touching externally at the point T. The tangent at T meets QR at P. If PT = 3.8 cm, then the length of QR (in cm) is
A. 3.8
B. 7.6
C. 5.7
D. 1.9
Attachments:
Answers
Answered by
8
Answer:
PT = PR = PQ [Tangents from a single exterior point are equal in length]
=> PQ + PR = 2PT = 2 × 3.8
=> 7.6 cm
Answer:- (b) 7.6 cm
____________
Answered by
0
Solutions:
PT = PR = PQ
PQ + PR = 2PT
PQ + PR = 2 × 3.8
PQ + PR = 7.6 cm
silentlover45.❤️
Similar questions