Question

In Fig. 10.37, find tan P and cot R. Is tan P = cot R?​

Answer 1

given= PQ =12cm

RP =13cm

RQ =?

for find RQ we use phythagarous therom

now,

H^2 = P^2 + B^2

RP^2=PQ^2+RQ^2

(13)^2=(12)^2+RQ^2

169=144+RQ^2

169-144= RQ^2

√25=RQ

5cm=RQ

So,

tan P=P/B = RQ/PQ = 5/12

cot R=B/P = RQ/PQ = 5/12

now,

tan P = cot R

5/12 = 5/12