Question

In Fig. 10.39, A, B, C and D are four points on a
circle. AC and BD intersect at a point E such
that angle BEC = 130° and angle BCD = 20°. Find angle BAC​

Answer 1

Answer:

BAC=∠CDE ...Angles in the segment of the circle

In ΔCDEΔCDE,

∠CEB = ∠CDE + ∠DCE∠CEB=∠CDE+∠DCE ...Exterior angles of the triangle

⇒ 130° = ∠CDE + 20°⇒130°=∠CDE+20°

⇒ ∠CDE = 110°⇒∠CDE=110°

Thus, ∠BAC = 110°∠BAC=110°

Answer 2

Answer:

110

Step-by-step explanation:

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