Question

In Fig. 10.72, PA and PB are tangents to the circle drawn from an external point P. CD are a third tangent touching the circle at Q. If PB = 10 cm and CQ = 2 cm, what is the length PC?

Answer 1

Answer☺️☺️⬇️⬇️:-

Step by step explanation =>

The two tangents drawn from an external point to a circle are equal in length.

Hence, we have

PA = PB

According to the given information, we have PB = 10 cm.

Thus, we get PA = 10 cm.

Using the same property of tangent as above, we have

CA = CQ = 2 cm

From the above figure, we can write

PC = PA − CA

By substituting the values of PA and CA in the above equation, we get

PC = 10 − 2

PC = 8 cm

In this way, we find that the length of PC is 8 cm

Hope it helps you ♥️♥️

Answer 2

Answer:

PA = PB = 10 cm [Tangents from a single exterior point are equal in length]

CQ = CA = 2 cm [Tangents from a single exterior point are equal in length]

=> PA - CA = 10 - 2 = 8 cm

Answer:- 8 cm

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