In Fig. 10.76, CP and CQ are tangents from an external point C to a circle with centre O. AB is another tangent which touches the circle at R. If CP = 11 cm and BR = 4 cm, find the length of BC.
[Hint: We have, CP = 11 cm
CP = CQ = CQ = 11 cm
Now, BR = BQ [Tangents drawn from B)
BQ = 4 cm
BC = CQ - BQ = (11 - 4)cm = 7 cm
Attachments:
Answers
Answered by
5
The length of BC is 7 cm.
Given,
CP = 11 cm
BR = 4 cm.
We know that tangents drawn from a same point to the same circle are equal
From figure it's clear that,
CP = CQ (tangents drawn from C)
BR = BQ (tangents drawn from B)
CP = CQ
11 = CB + BQ
11 = CB + BR
11 = CB + 4
11 - 4 = CB
∴ BC = 7 cm
Similar questions