In Fig. 10.79, RQ is a tangent to the circle with centre O. If SQ = 6 cm and QR = 4 cm, then OR =
A. 8 cm
B. 3 cm
C. 2.5 cm
D. 5 cm
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Answer:(d) 5 cm
Step-by-step explanation:
Given sq= 6
Therefore oq=3 (radius)
In traingle rqo,
Angle q= 90° ( radius perpendicular to tangent)
Therefore by pbt
Ro2 = qr2 + qo2
Ro2= (4)2 + (3)2
Ro2 = 16 + 9
Ro2 = 25
Ro = 5
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