Question

At one end of a diameter PQ of a circle of radius 5 cm, tangent XPY is drawn to the circle. The length of chord AB parallel to XY and at a distance of 8 cm from P is
A. 5 cm
B. 6 cm
C. 7 cm
D. 8 cm

Answer 1

Answer:

D 8 cm

Step-by-step explanation:

Let OD = x cm

OP = 8-x

Also OP = 5 cm ( radius)

5=8-x

X=OD=3 cm

In triangle AOD

By Pythagoras

OA^2=OD^2+AO^2

25 = 9 + AO^2

AO^2= 25 - 9 = 16

AO = 4

AB = 2 OA. :- OD is perpendicular bisector of AB

AB = 2 * 4 =8 cm

Answer 2

Step-by-step explanation:

i hope you like it !!!

OD is perpendiculr bisector thats why AB = 2×AD

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