Question

In Fig. 10.81, AP is a tangent to the circle with centre O such that OP = 4 cm and ∠OPA = 30°. Then, AP =
A. 2√2 cm
B. 2 cm
C. 2√3cm
D. 3√2 cm

Answer 1

Step-by-step explanation:

$op = 4cm \\ \cos(30) = \frac{b}{h} \\ \frac{ \sqrt{3} }{2} = \frac{ap}{4} \\ ap = 2 \sqrt{3} cm$

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It Option Is C)