Question

In Fig. 10.84, if AP = 10 cm, then BP =
A. √109cm
B. √127cm
C. √119cm
D.√109cm

Answer 1

Answer:

$B) \sqrt{127}cm$

Step-by-step explanation:

In rt triangle rt angled at A

AP=10 cm, OA=6 cm

PO=

$\sqrt{10^{2} +6^{2} }\\\sqrt{136}$

In rt triangle rt angled at B

BP=

$\sqrt{PO^{2}-OB^{2}}\\\sqrt{136-9}\\\sqrt{127}$

Answer 2

Answer:

your answer is in pic

Step-by-step explanation:

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