Question

In Fig. 10.96, if TP and TQ are tangents drawn from an external point T to a circle with centre O such that ∠TQP = 60°, then ∠OPQ =
A. 25°
B. 30°
C. 40°
D. 60°

Answer 1

Step-by-step explanation:

it is 30 degrees, as radius perpendicular to tangent, OQP= OPQ= 30 degrees

Answer 2

Answer:

B is the correct answer 30

Step-by-step explanation:

see triangle

ptq

angle TQO=90(tangent drawn from radius is perpendicular)

but

TQP =60

and

PQO=90-60

=30

SINCE TANGENTS DRAWN FROM EXTERNAL POINT ARE EQUAL THEREFORE THERE ANGLE IS ALSO EQUAL

QPO=30

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