Question

In Fig. 10.97, the sides AB, BC and CA of triangle ABC, touch a circle at P, Q and R respectively. If PA = 4 cm, BP = 3 cm and AC = 11cm, then length of BC is
A. 11 cm
B. 10 cm
C. 14 cm
D. 15 cm

Answer 1

Answer:

B. 10 cm

Step-by-step explanation:

TANGENTS FROM A SAME EXTERNAL POINT ARE EQUAL IN LENGTH

We shall this sole property throughout the whole solution:

AP=AR=4 cm

BP=BQ=3 cm

AC=11 cm

RC=QC=AC-AR=11-4=7 cm

BC=BQ+BC=3+7=10 cm

B. 10 cm