In fig 11.46, what is the value of x.
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Answered by
21
Answer:
7y+5y=180(linear pair)
12y=180
y=180/12
y=15°
so ATQ
5y=5x15
5y=75
3y=3×15
3y=45
5y+3y+x°=180( angle sum property)
75°+45°+x°=180°
120°+x°=180°
x=180-120
x=60°
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Answered by
10
Answer:
Angle ABC + Angle DBC = 180° (Linear Pair)
5y° + 7y° = 180°
12y° = 180°
y° = 180°/12
y° = 15°
Angle DBC = Angle BAC + Angle BCA (Exterior Angle Property)
7y° = 3y° + x°
7(15°) = 3(15°) + x°
105° = 45° + x°
x° = 105° – 45°
x° = 60°
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