Question

In Fig. 12.27, ABC is an isosceles triangle with AB = AC. P and Q
are points on AB and AC respectively such that AP = AQ.
(i) Is ∆ABQ=∆ACP
(ii) Is ∆BPC = ∆CQB ?
Give reasons in support of your answer.

PLZ TELL STEP BY STEP PLZ​

Answer 1

Step-by-step explanation:

1.If AP=AQ

Then, P=Q

Or, BP=CQ

2.AB=AC

3.AP=AQ

Hence, triangle ABQ=triangle ACP by SSS congruence criteria.

1. &2. If AP=AQ

Then, P=Q

Or, BP=CQ & BQ=CP

3.and BC=CB

Hence, triangle BPC=triangle CBQ by SSS congruence criteria.