In Fig, 17.17, ABCD is a parallelogram in which ZDA0 = 40°, ZBAO = 35°
and Z COD = 65°. Find:
(i) ZABO
(ii) ZODC
(ii) ZACB
(iv) ZCBD
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Answer:
(i) ZABO = 80°
(ii) ZODC = 80°
(iii) ZACB = 40°
(iv) ZCBD = 25°
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