Question

in fig 2 AB is the diameter of a circle with centre O​

Answer 1

60 degree is the answee

Answer 2

Answer:

the answer is 61 degree

Step-by-step explanation:

angle AOT=58 degree

OQ=OB

THIS IMPLIES ANGLE OBQ =ANGLE BQO

ANGLE OBQ+ANGLE OQT=ANGLE AOT (EXT ANGLE PROP)

2 ANGLE OBQ=ANGLE AOT

ANGLE  OBQ=58÷2

ANGLE OBQ=29 DEGREE

IN TRIANGLE ABT,

ANGLE(ABT+BAT+ATB)=180

ANGLE ATQ=180-90+29

ANGLE ATQ=61 DEGREE