Question

In fig 2,oapb is a sector of a circle of radius 3.5 cm with centre at o and angle aob =120°.Find the length of oapbo

Answer 1

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Answer 2

Length of the arc APB,

= $\sf{\frac{360 - 120}{360} \times 2\pi \: r}$

= $\sf{\frac{240}{360} \times 2 \times \frac{22}{7}\times 3.5cm}$

= $\sf{\frac{44}{3} cm}$

Hence, the length of OAPBO

= $\sf{OA+OB+arc\:APB}$

= $\sf{(3.5 + 3.5 + \frac{44}{3} )cm}$

= $\sf{(7 + \frac{44}{3} )cm}$

= ${\boxed{\sf{\frac{65}{3} cm}}}$