in fig 3.15, the bisectors of angle A and angle B meet at a point O. if angleC=100 and angleD=50, find angleAOB
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c+d=100+50
c+d=150°
a+b=360°-150° (a.s.p.)
a+b=110°
1/2 (a+b)=55°
1/2(a+b)+o=180°(a.s.p.)
55°+o=180°
aob(o)=180°-55°
Aob=125°
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