Question

In fig 3.28 the circles with centres A and B touch each other at E. Line L is a common tangent which touches the circles at C and D respectively.Find the length of seg CD if the radii of the circles are 4 cm, 6 cm.

Answer 1

Solution:-
given by :-
radii 4 cm and 6cm.
AB = 6+2 = 10 CM.
ANGLE (F ) = 90
then ,
BF = 6-4 = 2cm
IN TRIANGLE BFA
${ \: AF \: }^{2} = {A B}^{2} - {BF}^{2} \\ = {10}^{2} - {2}^{2} \\ AF = \sqrt{ 100 - 4} \\ AF = \sqrt{96} \\ AF = 4 \sqrt{6}$
AF || CD
HENCE,

$CD= 4 \sqrt{6}$
■I HOPE ITS HELP■

Answer 2

Answer:

Step-by-step explanation:

Solution:-

given by :-

radii 4 cm and 6cm.

AB = 6+2 = 10 CM.

ANGLE (F ) = 90

then ,

BF = 6-4 = 2cm

AF2=AB2-BF2

AF2=10(2)-2(2)

AF=√100-4

AF=4√6

IN TRIANGLE BFA

AF || CD

HENCE

proved.