In figure 3.37, points G, D, E, F are concyclic points of a circle with centre C. ∠ECF = 70°, m(arc DGF) = 200° find m(arc DE) and m(arc DEF).
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Solution:-
given by:-
》∠ECF = 70°,
》m(arc DGF) = 200°
》m(arc DE) = 360°-[m(arc DGF) + ∠ECF]
》= > 360° - (200+70)
》=> 360 - 270
》m(arc DE) =90° ans
》m(arc DEF) = m(arc DE) + ∠ECF
》=> 90+70
》m(arc DEF) = 160°ans
》hence,
》m(arc DEF) = 160°
》m(arc DE) =90°
■I HOPE ITS HELP■
given by:-
》∠ECF = 70°,
》m(arc DGF) = 200°
》m(arc DE) = 360°-[m(arc DGF) + ∠ECF]
》= > 360° - (200+70)
》=> 360 - 270
》m(arc DE) =90° ans
》m(arc DEF) = m(arc DE) + ∠ECF
》=> 90+70
》m(arc DEF) = 160°ans
》hence,
》m(arc DEF) = 160°
》m(arc DE) =90°
■I HOPE ITS HELP■
Answered by
64
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