In Fig. 4.57, AE is the bisector of the exterior ∠CAD meeting BC produced in E. If AB = 10 cm, AC = 6 cm and BC = 12 cm, find CE.
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SOLUTION :
Given : AE is the bisector of the exterior ∠CAD meeting BC produced in E and AB = 10 cm, AC = 6 cm, and BC = 12 cm.
CE = x cm
BE = (12 + x) cm
Since AE is the bisector of the exterior ∠CAD.
So, BE/CE = AB/AC
[The external bisector of an angle of a triangle divides the opposite side externally in the ratio of the sides containing the angle.]
(12+x)/x=10/6
6(12+x) = 10x
72 + 6x = 10x
10x - 6x = 72
4x = 72
x = 72/4
x = 18
Hence, CE = 18 cm
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Step-by-step explanation:
In ABC, AD is the bisector of ZA.
We know that, the internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.
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