Question

In Fig. 4.58, ΔABC is a triangle such that AB/AC = BD/DC ,∠B=70⁰, ∠C=50⁰ .Find ∠BAD

Answer 1

Answer:

hey mate here is your answer hope it helps you pls mark it as brainliest

Step-by-step explanation:

angleA+angleB+angleC=180

angleA+70+50=180

angleA=180-(70+50)

=180-120

=60degree

Answer 2

✦ Kindly refer to the attachment for the diagram.

$\frak{\red{Given:}} \begin{cases} \sf{\orange{\triangle ABC \; such \; that \; \dfrac{AB}{AC} = \dfrac{BD}{DC} }}\\ \\ \sf{\orange{\angle B = 70\degree\; \& \; \angle C = 50\degree}} \end{cases}$

$\frak {\red{Required \; to \; find: }} \sf{\orange{\;\angle BAD}}$

We know that,

In ΔABC,

∠A = 180 – (70 + 50) [Angle sum property of α triangle]

     = 180 – 120

     = 60°

Since,

$\implies \sf \dfrac{AB}{AC} = \dfrac{BD}{DC},$

AD is the angle bisector of angle A.

Thus,

$\sf \angle BAD = \angle\dfrac{A}{2} = \dfrac{60}{2} = 30^o$

                   $\boxed{\orange{\sf \therefore \angle BAD = 30^o}}$

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Hope it helps! :)