Question

In Fig. 6.13, lines AB and CD intersect at O. If
Z AOC + 2 BOE = 70° and BOD = 40°. find
EXERCISE 6.1
1.
< BOE and reflex 2 COE.
Fig. 6.13​

Answer 1

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Answer 2

given= ZAOC + ZBOE = 70

ZBOD = 40

To find = ZBOE = ?

Reflex of ZCOE = ?

Proof = ZAOC+ZCOE = 180

70 + ZCOE = 180

ZCOE = 180- 70

ZCOE = 110

Reflex of ZCOE = 360- 110

= 250

ZAOC = 40 ( Vertically opposite angle )

ZAOC + ZCOE + ZBOE = 180

40 + 110 +ZBOE = 180

ZBOE = 180- 150

ZBOE = 30 Answer