Question

please give me the solution of this question urgently​

Answer 1

Answer:

Question:

Tuning fork A produces 4 beats with tuning fork B of frequency 346 Hz. When tuning fork A is filed, the number of beats heard is 6 per sec. Find original frequency of Tuning fork A.

Given:

Beat frequency = 4 Hz.

Frequency of B = 346 Hz.

If Tuning fork A is filed, then beat frequency becomes 6

To find:

Frequency of Tuning fork A.

Concept:

We don't know if frequency of Tuning fork A is greater or lesser than that of Tuning Fork B

So, either of the 2 Equations can form :

$1) \: \: f_{a} - 346 = 4$

$2) \: 346 - f_{a} = 4$

Now , we know that if a tuning fork is filed, then it's frequency increases .

$So \: if \: value \: of \: f_{a} \: increases ,\: as \\ \: per \: the \: question ,\: the \: beat \: frequency \\ is \: also \: increasing.$

This is possible only in Equation (1)

So taking Equation (1) in consideration:

$\: \: f_{a} - 346 = 4$

$= > f_{a} = 346 + 4 = 350 \: hz$

So final answer is 350 Hz.