Question

in Fig 6: 15 , lines AB and CD intersect at 0 Aoc Boe = 40°, find Boe and reflex coe•​

Answer 1

Answer:

( The sum of angle in linear pair always equal to

180)

Step-by-step explanation:

(sum of angle in linear pair always equal to 180 )

∠AOC + ∠COE + ∠BOE = 180°

Given that ∠ AOC + ∠ BOE = 40° plug this value we get

= > 70° + ∠COE = 180°

= > ∠ COE = 180° -40°

= > ∠ COE = 140°

Also

(sum of angle in linear pair always equal to 180° )

∠COE + ∠BOE = 180°

Put ∠COE = 140°

140° + ∠BOE = 180°

= > ∠BOE = 180° - 140°

= > ∠BOE = 40°

Answer 2

Question :-

In figure, lines AB and CD intersect at 0. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

Answer :-

Since AB is a straight line,

∴ ∠AOC + ∠COE + ∠EOB = 180°

or (∠AOC + ∠BOE) + ∠COE = 180° or 70° + ∠COE = 180° [ ∵∠AOC + ∠BOE = 70° (Given)]

or ∠COE = 180° – 70° = 110°

∴ Reflex ∠COE = 360° – 110° = 250°

Also, AB and CD intersect at O.

∴∠COA = ∠BOD [Vertically opposite angles]

But ∠BOD = 40° [Given]

∴ ∠COA = 40°

Also, ∠AOC + ∠BOE = 70°

∴ 40° + ∠BOE = 70° or ∠BOE = 70° -40° = 30°

Thus, ∠BOE = 30° and reflex ∠COE = 250°.

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