in fig. 6.29,if AB||CD ,CD||EF and y:z = 3:7, find x
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39
Step-by-step explanation:
AB||CD ,CD||EF
y:z = 3:7
let y = 3a
z = 7a
L DOF = y = 3a ( vertically opposite angles)
L DOF + z = 180. (sum of interior angle)
3a + 7a = 180
10a = 180
a = 180/10
a = 18°
it means
y = 3a = 3×18 = 54°
z = 7a = 7×18 = 126°
x + y = 180°. (sum of interior angle)
x +54= 180
x = 180-54
x = 126°
Answered by
18
x=54°
Hope it helps you
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