In Fig. 6.32, if AB II CD, 2 APQ = 50° and A
PRD=1279, find x and y.
50°
1270
C Q
RD
Fig. 6.32
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Answer:
angle APQ=50°(given)
AB||CD(Given)
anglePRD=127°(given)
angleAPR=anglePRD(alternate interior angles)
angleY=angleAPR-angleAPQ
angleY=127-50
angleY=77°
angleX=angleAPQ(alternate interior angles)
angleX=50°
ANSWER:angleYis 77°whereas angleXis 50°.
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