Question

In Fig. 6.38, the sides AB and AC of ∆ABC are produced to points E and D respectively. If bisectors BO and CO of ∠ CBE and ∠ BCD respectively meet at point O, then prove that :
∠ BOC = 90° – $\frac{1}{2}$ ∠BAC.

Answer 1

Answer:

it is from NCERT Book example