Question

in fig 7 ABCD is a ||gm . CE bisects angle C and AF bisects angle A . in each of the following ,if the statement is true, give reason
CE||AF​

Answer 1

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Answer 2

Answer:

ABCD is a parallelogram, and AE and CF bisect ∠A and ∠C respectively.

To prove:- AE∥CF

Proof:-

Since in a parallelogram, opposite angles are equal.

∴∠A=∠C

⇒21∠A=21∠C

⇒∠EAF=∠FCE⟶(1)

Now, AB∥CD and CY is the transversal. So,

∠FCE=∠BFC⟶(2)

From eqn(1)&(2), we have

∠EAF=∠BFC

Transversal AB intersects AE and FC at A nad F such that ∠EAF=∠BFC

⇒AE∥FC

Hence proved.

Step-by-step explanation: